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Numerical Ability
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2^81 when divided by 6,what is the remainder
Read Solution (Total 13)
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- 2^81/6 ====> (2^1*2^2*2^3*....81 times]/6
2^1/6 ----------> remainder=2
2^2/6 -->4/6 ---> remainder=4
2^3/6 -->8/6 ---> remainder=2
2^4/6 -->16/6 --->remainder=4
2^5/6 -->32/6 --->remainder=2
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it goes on in a cyclic manner
so remainder is "2" for all odd powers of 2 nd "4" for all even powers of 2
here 2^81 which has the odd power
so remainder =2 - 10 years agoHelpfull: Yes(60) No(1)
- ((2^3)^27)/6
==>((8)^27)/6
==>(2^27)/6
==>((8)^9)/6
==>(2^9)/6
==>((8)^3)/6
==>(2^3)/6
==>8/6
so remainder is 2 - 10 years agoHelpfull: Yes(13) No(2)
- 2^odd/6------->remainder= 2.
2^even/6------>remainder= 4.
So, the answer is 2. - 10 years agoHelpfull: Yes(6) No(0)
- remainder= 1
proof:
2^81/6
= 4^80/6
=2^79/3
=2^(4+75)/3
=16^75/3...
& 3|16|5
15
----
1
since 16^n/3, remainder=1
16^75/3, remainder=1
hence proved...
- 10 years agoHelpfull: Yes(2) No(8)
- 2^81=2^80*2^1
so 2^80*2/6=2^8*10/3
now just take 2^8/3=256/3
which leaves a reminder of 1..so 1 is the ans - 10 years agoHelpfull: Yes(2) No(3)
- Ans: 1 ;(2^81)/(3x2)==>(2^80)/3==>even powers will give remainer 1 and odd powers will give remainder 2
- 10 years agoHelpfull: Yes(2) No(0)
- 2^81/(2*3)
=2^80/3
=(3-1)^80/3
=(-1)^80
=1 - 10 years agoHelpfull: Yes(1) No(2)
- let odd power of 2 is 3=8
8%6=2
next power 5=2^5=32
32%6=2
odd power of 2 when divided by 6 remainder is 2 - 10 years agoHelpfull: Yes(1) No(0)
- 2^81===2*4^40 =16^20*2/6 =rem2*4^20/6 2*16^10/6 =2*4^5/6 =8*16^2/6=2*4/6=2
- 10 years agoHelpfull: Yes(1) No(0)
- for every 4 divisivbles we get 2 so
for 81 th number we get 2 so it is divide at 0 we get remainder as 2
- 10 years agoHelpfull: Yes(1) No(0)
- 2^81
2 s unit sequence 2,4,6,8,0 so totally 5
81/5= 16 quot, 1 remaindr
in sequence list 1 ll be 2
so ans=2 - 10 years agoHelpfull: Yes(1) No(0)
- 4 is the answer...
- 10 years agoHelpfull: Yes(0) No(5)
- 2^81/6
->2^9/6=1
->2^9/6,2^9/6. . . . .2^9/6 total 9 times each one gives remainder one
so final remainder is 1
- 10 years agoHelpfull: Yes(0) No(4)
CTS Other Question
Eight friends P,Q,R,S,T,U,V And W go to a hotel to celebrate the birthday party, they all like different dishes viz. dosa, idli, momos, burger, pizza, kothe, parantha and bhatura.they are sitting around a circular table facing the center such that one person is sitting opposite to another personU does not like Burger but sits opposite to the person, who is near to the person, who like Dosa. The person who likes Parantha sits fourth to the left of the person, who is immediate right of H. Q sits third to the left of the person, who likes Idli. The person who likes Momos is Neither near the person, who likes Dosa nor opposite to Q. The person who likes Pizza is opposite to W, who is not near to the person who likes Dosa. U sits on the third place from the person who likes Momos. Person who likes Burger is on second place from the person who likes Idli and opposite to the person, who is immediate to the left of S. P is opposite of U but not near Q. The person who likes Kothe is opposite to T and they are not near to V. the person who likes Parantha is third to the right of PHow many friends are sitting between the person, who likes Kothe and the person who likes Bhatura?
Solve
(x-a)*(x-b)*(x-c)*...........(x-z)=?