Ken jogs at a rate of 8 miles per hour while Tom jogs at a rate of 6.5 miles per hour. If ken and Tom start at the same time and travel along the same route, how many hours will it Ken take to be 9.0 miles ahead of Tom?
Option
(a) .6 hours
(b) 13.5 hours
(c) 1.35 hours
(d) 6 hours

• K GOES AFTER X HR 8X MILE
  t GOES AFTER X HR 6.5x mile.
  so, 8x-6.5x=9
  x=6 hr
• 10 years agoHelpfull: Yes(2) No(0)
• (d) will be the answer
  As we can see from the options that in 6 hrs ken will travell 8*6=48 miles
  and Tom will travell 6.5*6=39 miles
  difference between distance travelled by both the runners=48-39=9
• 10 years agoHelpfull: Yes(1) No(0)
• ken's rate 8mph and tom's 6.5 mph
  so difference of distance in 1 hour = 1.5 miles
  so in 6 hours = 6 * 1.5 =9 miles
  so answer is (d)
• 10 years agoHelpfull: Yes(0) No(0)
• d)6hrs if in a hr he is 1.5km farword
• 10 years agoHelpfull: Yes(0) No(0)
• 6hr taken
  
• 10 years agoHelpfull: Yes(0) No(0)
• 9/1.5=6 hr
• 9 years agoHelpfull: Yes(0) No(0)
• ken jogs 1.5 mile more as compare to tom per hour
  to ahead 9 mile
  time=9/1.5=6 hours
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 8-6.5=1.5
  to be ahead of 9 miles,9/1.5=6hrs
• 6 years agoHelpfull: Yes(0) No(0)
• Relative speed =8-6.5 miles/hour=1.5miles/hr
  Time=distance/speed
  =9miles/1.5miles/hr
  =6hours
• 5 years agoHelpfull: Yes(0) No(0)