A train m leaves meerut at 5 a.m. and reaches delhi at 9 a.m. another train leaves delhi at 7 a.m. and reaches meerut at 10.30 a.m. at what time do the two trains_lavel3 cross each other ?

• 7:56am
  Let the total distance be x
  so the speed of 1st train is x/4 and 2nd train x/3.5
  In 2 hours 1st train covers half of the total distance .
  so remaining is only half of the total distance(ie x/2).
  let t be the time taken
  t*x/4 + t*x/3.5 = x/2
  t=14/15 i.e. 56 min
  ie
  total time taken= 2 hrs + 56 min
  time they cross each other is 7:56am (5+2.56)
  
• 10 years agoHelpfull: Yes(98) No(8)
• 7:56am
  Let the total distance be x
  so the speed of 1st train is x/4 and 2nd train 2x/7
  In 2 hours 1st train covers half of the total distance .
  so remaining is only half of the total distance(ie x/2).
  let t be the time taken
  t*x/4 + t*2x/7= x/2
  t=14/15 i.e.(14/15)*60 min= 56 min
  ie
  total time taken= 2 hrs + 56 min
  time they cross each other is 7:56am (5+2.56)
  
  
• 10 years agoHelpfull: Yes(8) No(8)
• Let the total distance be x
  so the speed of 1st train is x/4 and 2nd train x/3.5
  In 2 hours 1st train covers half of the total distance .
  so remaining is only half of the total distance(ie x/2).
  let t be the time taken.
  Now, the relative speed of 1st train with reference to 2nd train is
  (x/4) - (x/3.5) = x/28
  The time taken by the train to meet the 2nd train after 2 hrs is
  t = d/t
  = (x/2) / (x/28)
  56 min
  total time taken= 2 hrs + 56 min
  time they cross each other is 7:56am (5+2.56)
• 9 years agoHelpfull: Yes(4) No(3)
• answer is 7.56am
  
  
• 10 years agoHelpfull: Yes(0) No(4)
• @annnn can i get ur email id ..i have few questions need ur help so...
• 10 years agoHelpfull: Yes(0) No(16)
• using formula
  t=d/2(s1+s2)=d/2(d4+2d/7)
  taking d outside in deno
  t=d/2d(1/4+2/7)
  after taking lcm and cancelling d we ll get
  t=14/15
  t=7:56
• 4 years agoHelpfull: Yes(0) No(0)