Number of handshakes in a party is 28.Find the number of people present in the party altogether?

• no. of handshakes (ie) n(n-1)/2= 28
  
  therefore no. of people present
  n(n-1)=56
  n2-n-56=0
  n=8
  
  No. of people present = 8
  
  
  
• 10 years agoHelpfull: Yes(9) No(0)
• There will be total 8 People
  the shortcut formula is
  sigma(number of people - 1)
  if there will be 8 people then total combination
  7+6+5+4+3+2+1 = 28
  
• 10 years agoHelpfull: Yes(0) No(0)
• ANSWER: 15 members
  let y be number of shakehands
  similarly n members can give 2*(n-1)=y
  therefore n=y/2+1
  
  example:
  for example if there r 4 persons w,x,y,z
  
  w can give shakehand to w->x, w->y, w->z
  and x can give sh to x->y, x->z
  and y can give sh to y->z
  means 4 members can give 2*(n-1) shakehands. i.e, 2*(4-1)=2*3=6
• 10 years agoHelpfull: Yes(0) No(1)
• n*(n-1)/2 = 28 which on solving gives 8 , where n = number of people present.
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