A father's age is thirteen times that of his son. In 10 years, the son's age will be one-third of his father's. How old are the father and son?

• 26 & 2 years
  
  If age of father=x, son=y
  x=13y ---(i) &
  (x+10)=3(y+10) ---(ii)
  Solving (i)&(ii), x=26, y=2
• 10 years agoHelpfull: Yes(1) No(0)
• LET THE AGE OF FATHER IS 'F'
  SON IS 'S'
  NOW GIVEN THAT
  F=13S
  F-13S=0.......(1)
  1/3(F+10)=S+10
  F+10=3S+30
  F-3S=20....(2)
  BY SOLVING EQ 1 AND 2
  WE GET
  SON AGE =2YR
  FATHER AGE =26YR
  
• 10 years agoHelpfull: Yes(0) No(0)
• let son age be x
  then father age is 13 times of son means 13x
  after 10 years
  the age of son will be x+10 and father =13x+10
  where condition is son age is one third of father that means
  
  (13x+10)/3=x+10
  13x+10=3(x+10)
  13x+10=3x+30
  therefore 10x=20 and x=2
  
  then present father age = 13x = 13(2)=26
  present son age =x=2
  
• 10 years agoHelpfull: Yes(0) No(0)