For the same amount of work carpenter A takes 6 hours less than carpenter B, if together they complete the work in 13 hrs 20 min; in how much time will carpenter B alone complete the work?

• A..24 hrs
  B... 30 hrs
• 10 years agoHelpfull: Yes(3) No(1)
• Let time taken by A and B be x and (x+6)
  
  x(x+6)/(x+x+6) = 13 hrs 20 min
  x(x+6)/(2x+6) = 40/3 hrs
  
  3x(x+6) = 40(2x+6)
  solving x = 24
  
  Time taken by
  A= 24 hrs
  B = 30 hrs
• 10 years agoHelpfull: Yes(3) No(2)
• A ll finish 6 hours before B
  So A = B-6 ---->(1)
  
  Both ll finish in 13 hrs 20 min (ie) 40/3 hrs
  
  A + B 's 1 hr work is
  
  1/B-6 + 1/B = 3/40
  B+B-6/B^2-6B = 3/40
  3B^2-98 +240 = 0
  
  After factorizing , v ll get B = 8/3 nd B = 30
  
  Take whole number (ie) B=30
  
  so A = B-6 =====> A = 30 - 6 = 24
  
  
  B alone ll complete d work in 30 days
• 10 years agoHelpfull: Yes(3) No(2)
• sorry its 30 hrs not days
  
  B alone ll finish in 30 hrs
• 10 years agoHelpfull: Yes(1) No(1)