5 men and 8 boys can complete a work in 5 days . the same work would also be completed by 6 men and 3 boys number of days required by 2 men and 5 boys to complete the same work is

• 11 days
  
  M--->men B--->boys
  
  5M + 8B --->5days --(1)
  6M + 3B --->5days --(2)
  ===> from (1) and (2) 1M = 5B
  
  Substituting in (1)
  ie, 33B ---->5days
  
  2M + 5B = 15B
  Let x be no of days taken by 2 men and 5 boys
  
  33B---5days
  15B---xdays
  
  x = 33*5/15 = 11days
• 10 years agoHelpfull: Yes(1) No(5)
• question is incomplete. duration of work completion by 6 men and 3 boys is not given.
• 10 years agoHelpfull: Yes(0) No(0)