In 7 years, Maria will be four times as old as Angelica will be then. The sum of their ages now is 71. How old will each of them be in 5 years?

• Let M nd A be the current ages of Maria nd Angelica
  Given
  
  (M + 7) = 4( A + 7)
  M = 4A + 28 -7
  M = 4A + 21 ---->(1)
  
  Given
  M + A = 71
  M = 71 - A ---->(2)
  
  Equate d 2 equations
  v ll get
  
  71 - A = 4A + 21
  A = 10
  
  M = 71 - A
  M = 71 - 10
  M = 61
  
  Present age of Maria = 61
  Present age of Angelica = 10
  
  After 5 years
  
  Maria = 61+5 = 66 years
  Angelica = 10+5 = 15 years
  
  
  
  
  
  
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