Rahim plans to drive from city A to station C, at the speed of 70 km per hour, to catch a train arriving there from B. He must reach C at least 15 minutes before the arrival of the train. The train leaves B, located 500 km south of A, at 8:00 am and travels at a speed of 50 km per hour. It is known that C is located between west and northwest of B, with BC at 60° to AB. Also, C is located between south and southwest of A with AC at 30° to AB. The latest time by which Rahim must leave A and still catch the train is closest to

6:15 am
6:30 am
6:45 am
7:00 am
7:15 am

• Cities A,B,C are lying on a triangle ABC
  in which
  angle A=30 B=60,c=90
  AC =250 sq rt 3 = 433 kms, AB=500, BC = 259 km
  time taken by train from B to C = 250/50 = 5 hrs
  Rahim should reach before 8:00+5hrs-15min=12:45 pm
  Time taken by Rahim to travel = 433/70 = 6.18 hrs = 6 hrs 11 mins
  thus should leave b4 12:45-6:11=6:34
  hence He must leave by 6:30 AM....... option B
• 13 years agoHelpfull: Yes(5) No(1)
• 
  The latest time by which Rahim must leave A and still catch the train is closest to 6:30 am.
• 13 years agoHelpfull: Yes(2) No(1)