sachine has certain average for 9 innings.in the tength innings he scores 100 thereby increasing his average by 8 runs..thus the new average is

• Let "x" be the total , nd "y" be the avg till 9th innings
  
  then x/9 = y =====> x = 9y ---->(1)
  
  x + 100/ 10 = (y + 8)
  x + 100 = 10y +80
  9y + 100 = 10y + 80
  y = 20
  
  Avg till 9th innings = 20
  After 10th innings = 20 + 8 = 28
  
  So new average = 28
• 10 years agoHelpfull: Yes(9) No(0)
• 28
  
  Let the average be x
  
  (9x+100)/10 = x+8
  x = 20
  
  new average = x+8 = 28
• 10 years agoHelpfull: Yes(2) No(0)
• New average is 28
  
• 10 years agoHelpfull: Yes(1) No(0)
• x/9=y
  x=9y
  now (x+100)/10=y+8
  (9y+100)/10=y+8
  9y+100=10y+80
  y=100-80
  y=20
  so new avg=y+8=20+8=28
• 10 years agoHelpfull: Yes(0) No(0)
• according to the equation
  
  (x+100)/10=(x/9)+8
  
  on solving x(i.e..avg upto 9 innings) =180
  
  so new avg = (180+100)/10 =28
• 10 years agoHelpfull: Yes(0) No(0)