1 2 3 3 4 21 5 6 55 7 8

1 + 2 => (1)^2 + (1*2) = 3
3 + 4 => (3)^2 + (3*4) = 21
5 + 6 => (5)^2 + (5*6) = 55
Thus 7 + 8 => (7)^2 + (7*8) = 105

Ans : 105
10 years agoHelpfull: Yes(3) No(0)
1+2=3 3*1=3
3+4=7 7*3=21
5+6=11 11*5=55
7+8=15 15*7=105
so ans is:105
10 years agoHelpfull: Yes(1) No(0)
First, do the sum of two no.then multiply the sum with first number.solution is given below......
1+2=3*1=3
3+4=7*3=21
5+6=11*5=55
7+8=15*7=105
10 years agoHelpfull: Yes(0) No(0)
1+2=>3*1=>3
3+4=>7*3=>21
5+6=>11*5=>55
7+8=>15*7=>105
8 years agoHelpfull: Yes(0) No(0)

1+2=3
3+4=21
5+6=55
7+8=?