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Related to direction & distance: a person is travelling in so and so direction, eg: 5km North then 5km East then 10km North then so and so. Find the distance between original & final positions
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- Let the distance be x. Hence x^2=15^2+5^2=250 .so x=15.8km
- 9 years agoHelpfull: Yes(3) No(0)
- ans:15.8
5km east,15km north
sqrt[(5*5)=(15*15)]=15.8 - 9 years agoHelpfull: Yes(1) No(1)
- as the question goes,the distance would be 10 km north+ 5km north+5km east=20
- 10 years agoHelpfull: Yes(0) No(1)
- please sumbit sol??
- 10 years agoHelpfull: Yes(0) No(0)
- plzee explain..??
- 10 years agoHelpfull: Yes(0) No(0)
- sqrt((5+10)^2+5^2)=15.8113
- 9 years agoHelpfull: Yes(0) No(0)
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