Man, woman and a boy finish work together in 6 days. Man alone takes 10 days; woman alone takes 24 days then how many days boy alone will take to do that work?

• Let M, W , B be man, women, nd boy
  
  M + W + B 's 1 day work = 1/6
  M's 1 day work = 1/10
  W's 1 day work = 1/24
  M + W's 1 day work = 1/10 + 1/24 ==> 34/240 = 17/120
  
  B's 1 day work = (M + W + B) - (M + W)
  ==========> 1/6 - 17/120 ==> 120 - 102/720
  ==========>18/720 = 1/40
  
  So boy alone ll finish d work in 40 days
  
  Ans : 40 days
• 10 years agoHelpfull: Yes(42) No(0)
• m+w+b=1/10
  1/10+1/24+1/x=1/6
  1/x=1/40
  time=40days
  
• 10 years agoHelpfull: Yes(6) No(0)
• 1 day work of B,M,W=100/6= 16.66%
  1 day work of man=100/10= 10%
  1 day work of woman=100/24= 4.16% then 1 day work of boy= 16.66-(10+4.16)=2.5%
  so day taken to complete the total work(100%) = 100/2.5= 40 days
• 10 years agoHelpfull: Yes(3) No(0)
• m=10d
  w=24d
  b=?
  m+w+b=6d
  l.c.m of 10,24 is 120
  then ,
  m=120/10=12
  w=120/24=5
  m+w=17
  m+w+b=120/6=20
  17+b=20
  b=3
  for 3 days boy can do=120/3=40days
• 6 years agoHelpfull: Yes(2) No(0)
• work done in 1 day by,
  man->1/10
  woman->1/24
  boy->1/x
  6(1/10+1/24+1/x)=1
  so,x=40
  boy takes 40days
• 10 years agoHelpfull: Yes(1) No(0)
• 1/6 - 1/10 - 1/24 = 1/40
  40 days
• 10 years agoHelpfull: Yes(1) No(0)
• 1/6-(1/10+1/24)
  answer is 1/40=40days
• 10 years agoHelpfull: Yes(1) No(0)
• Ans:40
  
  Man one day work=1/10
  woman one day work=1/24
  Man and woman works is=1/10*1/24=34/240
  =17/120
  
  Together one day works is=1/6
  
  boy alone works is=>>1/6-17/120=>>120-102/720=>>18/720=1/40
  
  So boy alone works is 40
• 10 years agoHelpfull: Yes(1) No(0)
• man 1/10
  
  woman 1/24
  
  boy 1/x
  
  together 6
  1/10* 1/24* 1/x = 6 so 240x=6 x=240/6 =40
  
• 10 years agoHelpfull: Yes(1) No(0)
• n 6 days men will do (1/10)*6=6/10=3/5 part of work..
  while women will do (1/24)*6=6/24=1/4 part of work
  it mens rest of work wil; be done by boy...i:e 1-{(3/5) + (1/4)}=3/20
  boy is doing 3/20 work in 6 days
  so..........1/20 work .........2 days
  now 1 complete work ......2*20=40days
  40days is the answer
• 6 years agoHelpfull: Yes(1) No(0)
• 40 days.efficiency of man=10,efficiency of woman=4.16.total efficiency=16.67.
  boys efficiency=16.67-14.16=2.50.no of days taken by boy=100/2.50=40
• 10 years agoHelpfull: Yes(0) No(0)
• xyz/(xy+yz+zx)=6
  x=?
  y=10
  z=24
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 10 years agoHelpfull: Yes(0) No(2)
• man's work in one day=10%; woman's work in one day=4.167%
  work done by all of three in one day=16.67%
  let work done by boy in one day=x%
  therefore,10+4.167+x=16.67
  so,x=2.5%
  boy does same work in 100/2,5=40 days
• 10 years agoHelpfull: Yes(0) No(0)
• man+woman+boy=1/6 and man=1/10,woman=1/24 then
  1/10+1/24+boy=1/6 then boy=1/6-(1/10+1/24)
  1/6-1/120=19/120
  then boy can alone do a work in 120/19 day
• 10 years agoHelpfull: Yes(0) No(2)
• x-10/20 + x/30 =1
  then x=18 is correct.
• 10 years agoHelpfull: Yes(0) No(1)
• Boy will take 40days
• 10 years agoHelpfull: Yes(0) No(0)
• one day work of M+W+B = 1/6
  One day work of M = 1/10
  One day work of W= 1/24
  1/10 + 1/24 + B = 1/6
  B = 1/6-1/10-1/24
  = (20-12-5)/120
  = 3/120
  B = 1/40
  Therefore, boy alone take 40 days
• 6 years agoHelpfull: Yes(0) No(0)
• m+w+b=1/6
  m=1/10
  w=1/24
  1/10+1/24+b=1/6
  b=1/40
  i.e.,40 days
• 6 years agoHelpfull: Yes(0) No(0)