10 men or 18 children can finish a work in 15 days in how many days 25 men and 15 children can finish the double work

• work done by 1 men in 1 day = 1/150
  work done by 1 child in 1 day = 1/270
  work done by 25 men in 1 day = 1/6
  work done by 15 children in 1 day = 1/18
  work done by 25 men and 15 children in 1 day = 1/6 + 1/18 = 2/9
  so it will take them 4.5 days to complete the work.
  Since work is twice it will take them 9 days
• 10 years agoHelpfull: Yes(1) No(0)
• 10 men = 18 children (as their time for same work is same)
  5 M=9 C (M= men , C=children)
  
  ATQ
  25 M +15C =?
  using above equation
  25M = 45 C
  SO 45C+ 15C= 60C
  
  60C*X=18*(15*2) (WORK = DAYS *WORKERS) (15*2= MENTIONS DOUBLE WORK)
  
  
  X=9 DAYS ans
• 6 years agoHelpfull: Yes(1) No(0)
• ans: 9 days
  
  Since the work is doubled
  
  10 men --->30 days
  18 children ---->30days
  
  Let 25 men take x days
  
  10 men---30days
  25 men---x days
  
  x = 10*30/25
  = 12days
  
  Let 15 children take y days
  
  18 children---30days
  15 children---y days
  
  y = 18*30/15
  = 36days
  
  Since the work is done by both men and children
  
  number of days required = 12*36/(12+36)
  = 12*36/48
  = 9 days
• 10 years agoHelpfull: Yes(0) No(0)
• here 10 men is equal to 18 children.
  so 25 men is equal to 45 children.
  so total children is 45 children + 15 children= 60 children.
  18 children can finish in 15 days.
  so 60 children can finish in 4.5 days..
  thats it....
• 10 years agoHelpfull: Yes(0) No(2)
• AS PER GIVEN DATA
  10M=18C
  DIVIDE IT BY 2
  5M=9C
  NOW MULTIPLY IT WITH 5
  25M=45C
  NOW WE CAN WRITE
  25M&15C AS 45C+15C=60C
  18C--->15D
  60C-->X
  X=18*15/60
  X=4.5DAYS
• 4 years agoHelpfull: Yes(0) No(0)