if m=2√3 then value of √m+(1/√m) is

• [√m+(1/√m)]^2 = m + (1/m) + 2
  
  => [√m+(1/√m)]^2 = 2√3 + (1/2√3) + 2
  
  => [√m+(1/√m)]^2 = 2√3 + (1/6)√3 + 2
  
  => √m+(1/√m) = √[(13/6)√3 + 2]
  
• 10 years agoHelpfull: Yes(35) No(3)
• Vm + ( 1 / Vm) = 3V2 + ( 1 / 3V2)
  ============> 18+1/3V2 = 19/3V2 [here V - root symbol]
  
  Ans : 19V2/6
• 10 years agoHelpfull: Yes(19) No(18)
• given that m=2V3 substitute value of 'm' in given expression then we get
  
  3V2+(1/3V2)= 3*1.414+(1/3*1.414)=4.32+(1/4.32)=4.32+0.23 = 4.55
  
• 10 years agoHelpfull: Yes(3) No(3)
• i dint undstn plz anyone can explain clearly
• 10 years agoHelpfull: Yes(3) No(0)
• Ans. 3.75
  
• 10 years agoHelpfull: Yes(2) No(0)
• plz substitute m=2v3 not 3v2...
  
• 10 years agoHelpfull: Yes(1) No(3)
• Vm+(1Vm)=m+1Vm=2Vm+1V2V3..........
• 10 years agoHelpfull: Yes(1) No(1)
• not understood i think its sign of square root not v
• 8 years agoHelpfull: Yes(0) No(0)
• 1/(2(3)^1/2)^1/2=0.537
  (2(3)^1/2)^1/2+0.537=2.39
• 7 years agoHelpfull: Yes(0) No(0)