If a person moves 15km straight and turns right and moves 15km straight then how much distance he needs to walk to reach starting point?

• person will move along right angled traingle whose smaller sides are 15 km
  & 15 km
  reqd distance= hypotenuse of triangle = √(15^2+15^2)= 15√2 = 21.2 km
• 10 years agoHelpfull: Yes(25) No(2)
• Ans-----> 15*(2)^1/2 km
  
  at first draw diagram
  
  so, from the diagram------>
  
  distance to reach starting point ==> d^2 = 15^2 + 15^2
  d= 15 * (2)^1/2 km
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• 21.21
  By pythagoras theorem
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• sqrt(15^2+15^2)=15 sqrt(2)
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• hypotenuse of triangle = √(15^2+15^2)= 15√2 = 21.2 km
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• (15^2
  +15^2)^1/2=450^1/2=21.21 approx.
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• if base is 15km and height is 15km then
  by pythagoras theorm,
  
  (hypotanious)^2 = (base)^2 + (height)^2
  so distance=square root(15^2 + 15^2)
  =15 * square root(2)
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• ans is 21.2
  [15^2+15^2]^1/2 = 450^1/2=21.2 somethig
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• the distance between starting point and final point is sqrt(15^2 +15^2)
  =>15sqrt2
  15sqrt2 km he needs to walk to reach starting point
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• 15 as de same distance he flows on so ans is 15
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• root over (15^2+15^2)=15root2
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• ans 21.210
  
  
  
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• THIS IS NOT TCS QUETSION THIS IS 7TH CLASS GOVERNMENT SCHOOL QUESTION
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