An engineering staff consist of 14 persons of whom 25% are mathematicians, to obtain a team consisting of 10/12 mathematicians. How many more mathematicians should be hired

• Let initially Mathematicians be M0.
  Given M0=14*0.25
  Now to make a team of 10/12 Mathematicians engineers, lets add x no of engineers(who are mathematicians).
  So, (M0+x)/(14+x)=10/12
  =>x=49
  Answer 49 mathematicians should be hired
• 10 years agoHelpfull: Yes(20) No(3)
• If a team consists 14 persons in which 25% are mathematicians then
  14*(25/100)=3.5
  
  If x mathematicians are hired so that the ratio would become 10/12, then
  (3.5+x)/(14+x) = 10/12
  12*(3.5+x) = 10*(14+x)
  42+12x = 140+ 10x
  x= 49
  
  
• 9 years agoHelpfull: Yes(16) No(0)
• 7/12
  Present mathematician in 14 person=14*25/100=7/2, i.e. 7/2 in 14 person or 7/28
  If mathematicians to be hired=x
  (7/28)+x=(10/12), x=7/12
• 10 years agoHelpfull: Yes(5) No(8)
• 10/12=0.833
  now mathe... avaliable 25%=0.25
  so, 0.25+x=0.833
  ans:0.583 ~ 7/12
• 10 years agoHelpfull: Yes(3) No(5)
• 25/100*14=7/2
  to obtain 10/12 maths team,we have to add some x to the 7/2
  so x=7/2-10/12=8/3
• 10 years agoHelpfull: Yes(1) No(8)
• Which is the correct answer
• 10 years agoHelpfull: Yes(1) No(0)
• 100%----------14
  25%-----------7/2(3.5)
  from this i can say that we cannot determine the answer becoz
  from (3.5) generally 3 persons are mathematicans and what is 0.5 mean??????
  so ans:can't determine
  
• 10 years agoHelpfull: Yes(1) No(2)
• hi friends explain clearly in your method i didn't get ans is 49
• 10 years agoHelpfull: Yes(0) No(1)
• 10). (8,22,54,86)
  (6,26,58,90)..here
  8-22=14,22-54=32,54-86=32;
  6-26=20,26-58=32,58-90=32;
  4-30=26..
  ans is (4,30,62,94)
• 10 years agoHelpfull: Yes(0) No(0)