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There is well of depth 30m and frog is at bottom of the well. He jumps 3m in one day and falls back 2m in the same day. How many days will it take for the frog to come out of the well?
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- 28 days
frog jumps 3 m in day & falls back 2 m at night
so,frog will be 3-2=1 m up in a day.
thus, in 27 days it will be 27 m up
on 28 th day it will be at top i.e 27+3 = 30 m & willnot fall down. - 10 years agoHelpfull: Yes(132) No(0)
- 28 days.........because the frog jumps 1m for a day as by 3up and 2 falls...so up to 27days it will jump to 27m...in 28thday it will jump to 3m that means it was acheived
- 10 years agoHelpfull: Yes(8) No(0)
- the frog jumps for 3ms in a day and falls back 2m's in the same day.
so it jumps 1m per day
so it takes 27 days to go for 27m's and on 28th day it reaches top
so ans. 28 days - 10 years agoHelpfull: Yes(4) No(0)
- Total depth 30m
per day 3-2=1
27 days 27m.
28th day it reaches top means 30m,
28 days is the answer - 10 years agoHelpfull: Yes(3) No(0)
- per day 1m.after 27 it takes one day thus 28
- 10 years agoHelpfull: Yes(2) No(0)
- 28 days...
In 27 days frog reached to 27 m
On 28th day =27+3=30m - 10 years agoHelpfull: Yes(1) No(0)
- 28 days
if he jumps 3 mts and falls 2mts down then he jumps 1 mt in a day
in 27 days he will jump 27days, on the 28th day he will jump 3mts and once he reaches 30mts he will not fall back again
- 10 years agoHelpfull: Yes(1) No(0)
- 30 days...because every day he climbs up 1 mtr (3-2)
- 10 years agoHelpfull: Yes(1) No(9)
- 3*30-2*30=90-60=30 meters
so it will take 30 days - 10 years agoHelpfull: Yes(1) No(10)
- 30 days
on one day (3m - 1m) =1m
so for 30m = 30 days - 10 years agoHelpfull: Yes(0) No(12)
- it' 28
as 3-2=1
so in 27 days he will be 27 m up and in 28 day he will be out of the well. - 7 years agoHelpfull: Yes(0) No(0)
- 3 up - 2 down = 1 up (per day)
therefore, 27up=27m in 27 days +1 day (3up) = 30m.
total days = 28. - 5 years agoHelpfull: Yes(0) No(0)
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