Two trains start at the same time from Aligarh and Delhi and proceed towards each other at 16 kmph and 21 kmph. respectively. when they meet it is found that one train has travelled 60 km more than the other the distance between the two stations is

• 444 km
  
  Let
  y---> distance travelled by 1st train
  x---> distance travelled by 2nd train
  
  x/21 = y/16---(1)
  
  x = y+60----(2)
  
  Substitute (2) in (1)
  
  (y+60)/21 = y/16
  16y + 960 = 21y
  y = 192
  x = 252
  
  Distance between 2 stations = x+y
  =252+192
  =444 km
• 10 years agoHelpfull: Yes(3) No(0)
• Speed Distance Time
  16 x t
  21 x+60 t
  
  equating to time 16*(x+60) = 21x
  ====> 5x = 60*16
  ====> x = 192
  total distance = x+(x+60)
  = 444
  
• 10 years agoHelpfull: Yes(3) No(0)
• 't' is the time taken to meet one point
  distance travelled by first train is = 16 t,
  distance travelled by second train is = 21 t,
  distance between them is 60,
  so the 21t-16t=60 by solving this we get the answer t=12 hrs
  distance between them is = 21t+16t
  = 21*12 + 16*12
  = 444
• 10 years agoHelpfull: Yes(2) No(0)
• let, t be the time when the trains meet each other.
  so, 21t - 16t = 60
  => 5t = 60
  => t = 12
  so, the distance between the two stations = 21t + 16t
  = 37t
  = 37*12
  = 444 Km . (ans)
• 9 years agoHelpfull: Yes(2) No(0)
• 192 km distance more
• 10 years agoHelpfull: Yes(0) No(2)