Q. What is the next number of the following sequence
60, 15, 108, 27, 156, 39, ....

• 60,15,108,27,156,39
  (60,15),(108,27),(156,39),(x ,x/4)
  
  60/15 = 108/27 = 156/39 = 4
  
  1st term of each pair
  60,108,156,x
  12*5=60
  12*9=108
  12*13=156
  12*17 = 204
  
  next two term = (x, x/4) = 204, 204/4
  
  ans: 204,51
• 10 years agoHelpfull: Yes(20) No(1)
• in this series
  (60,108,156)(15,27,39)
  60+48=108
  108+48=156
  156+48=204
  and
  15+12=27
  27+12=39
  39+12=51
  ans=204,51
• 10 years agoHelpfull: Yes(7) No(0)
• (60 15) =15*4=60
  (108 27)=27*4=108
  (156 39)=39*4=156
  now lets c...
  (60 108 156)
  108-60=48
  156-108=48
  therefore 156+48=204
  answer=204
• 10 years agoHelpfull: Yes(1) No(0)
• 39+12=51
  51*4=204
  so next no are 204 & 51
• 10 years agoHelpfull: Yes(0) No(0)
• ans-204
  
  15*4=60
  27*4=108
  39*4=156
  
  now 15/3=5
  27/3=9
  39/3=13
  
  so next no after 5,9,13=17
  17*3=51
  51*4=204
  
  ans 204,51
  
• 10 years agoHelpfull: Yes(0) No(0)
• 60+48=108 108/4=27
  108+48=156 156/4=39
  156+48=204 204/4=51
  
  so ans:204,51
• 10 years agoHelpfull: Yes(0) No(0)
• 156+48=204
• 10 years agoHelpfull: Yes(0) No(0)