Q. What is the next number of the following sequence
32, 29, 26, 64, 61, 58, 96, 93, 93, ...

• 32,29,26,64,61,58,96,93,93
  (32,29,26),(64,61,58),(96,93,93),(x,x-3,x-6)
  
  32-3=29,29-3=26
  64-3=61,61-3=58
  96-3=93,93-3=60
  
  take 1st term of each group
  32,64,96,x
  32*1=32
  32*2=64
  32*3=96
  32*4=x => 128
  
  next three numbers= (x,x-3,x-6)= (128,125,122)
• 10 years agoHelpfull: Yes(28) No(2)
• There is a misprint in the series. It should be:
  32, 29,26, 64,61,58, 96,93,90, ?,?,?
  now,
  [32,29,26], [64,61,58], [96,93,90]
  the series is [32, 32-3, 32-6], [32*2=64, 64-3, 64-6], [32*3=96, 96-3, 96-6]
  next will be: [32*4=128, 128-3,128-6]
  so, 128,125,123...
• 10 years agoHelpfull: Yes(11) No(0)
• 128
  32*2=64, 32*3=96, 32*4=128
• 10 years agoHelpfull: Yes(0) No(0)
• 128 32+29=61; 32+26=58;so on 32+96=128
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 87
  32,26,61,96,93 one series
  29,64,58,93,? other series
  64-29=35
  64-58=6
  93-58=35
  93-87=6
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 96+32=128 and the last 93 should be 90
• 10 years agoHelpfull: Yes(0) No(0)