Dhoni when hits a boundary he swings his bat. When he hits a boundary he swing his bat 4 time and when he hits a six he swings his bat 7 time .when he hit 2 boundary he swing his bat for both the boundary i.e. say he hits a four first then he swings 4 time. Next when he hits a six or four he swings his bat 4+7(for six) 4+4(for four),and so on.so for 3 boundary say 4,6,4 he swings 4,4+7,4+7+4 numbers of times. In total he swings 4+4+7+4+7+4 number of time. 1) dhoni swings his bat for 99 times, find out number of way he can hit boundary.

• four ways
  23 four 1 six
  16 four 5 six
  9 four 9 six
  2 four 13 six
  now combination of these possibilities are :-
  24C1+21C5+18C9+15C2 = 24+20349+24310+156=44839
• 10 years agoHelpfull: Yes(18) No(19)
• there are four ways.
  1.464444
  2.644444
  3.444664
  4.66646
• 10 years agoHelpfull: Yes(10) No(8)
• total no of swings =99 which is equal to ( 4*23 + 7*1 =99)
  therefore, no of ways he can hit the boundary = (4 + 4+.....22 times + (4+7)once)=23 times.
  
  
• 10 years agoHelpfull: Yes(4) No(9)
• There are two ways
  1st way==[4,4+7,4+7+4,4+7+4+4,4+7+4+4+4,4+7+4+4+4+4]
  2nd way==[4,4+4,4+4+4,4+4+4+7,4+4+4+7+7,4+4+4+7+7+4]
• 10 years agoHelpfull: Yes(4) No(3)
• 7X+4y=99 in only 5 ways he can score 99 runs 7*1+4*23,7*3+4*22,7*5+4*16,7*9+4*9,7*13+4*2
• 10 years agoHelpfull: Yes(2) No(16)
• there is only one way .......4,4,4,6,6,4........so no of swings
  4+8+12+19+26+30 = 99
• 10 years agoHelpfull: Yes(2) No(9)
• there is one way ...
  4,4,4,6,6,4
  it means -> ( 4,4+4,4+4+4,4+4+4+7,4+4+4+7+7,4+4+4+7+7+4 ) = 99
• 10 years agoHelpfull: Yes(2) No(4)
• alok kumar.....what abt 4,6,4,4,4,4 i.e, 4+11+15+19+23+27 =99
  it is also the way....so ye majduro k tarike se solve nhi hoga....kuch alag logic lgao
• 10 years agoHelpfull: Yes(2) No(10)
• 4 ways........
  23 four 1 six
  16 four 5 six
  9 four 9 six
  2 four 13 six
• 10 years agoHelpfull: Yes(1) No(5)
• i can't understand this question. how to understand step by step
• 10 years agoHelpfull: Yes(0) No(4)
• 4*x+7*y=99..thus x can be 2,9,16,23 and y can be 13,9,5 respectively...when 2 boundaries only one combination i.e 6,66,666,6664,66646..when 9 4's and 9 6's two combinations ...as are equal so will rearrange each other again 16,5..only 1 again 23,1..only one condn i.e hit four at last ball..thusin total=1+2+1+1==5
• 10 years agoHelpfull: Yes(0) No(4)
• Here he can hitq 4,6,4,4,4,4.after this question is asking how many ways so we use p and c 6!/4!=30 ways
• 10 years agoHelpfull: Yes(0) No(2)
• There is only one way to hit 99 boundaries
  because every time he hit boundary previous no. of swings is been added to current boundary swings
  So.
  1+2+3+4+5+6+...no of terms increases
  now 2+13=15,
  And 1+2+3+4+5=15
  so this is the possible combination
  and 9+9=18,
  1+2+3+4+5+6=21
  similarly,others(23+1=24, 16+5=21,) don't satisfies this condition
  
• 10 years agoHelpfull: Yes(0) No(3)