The length of minute hand of a clock is 5.4 cm. What is the area covered by this in 10 minutes

• area of circle is pi*r^2
  but in 10 minutes area covered is (10/60)*360=60 degree
  so formula is pi*r^2*(angle/360)=3.14*(5.4^2)*(60/360)=15.27 cm^2
• 10 years agoHelpfull: Yes(31) No(1)
• 4.86*pi cm square
  
  Angle made in 10 min = 10/60*360
  =60 degree
  
  Area of sector = n/360*pi*r^2
  =60/360*pi*5.4*5.4
  =4.86*pi cm^2
• 10 years agoHelpfull: Yes(5) No(1)
• A=n/360*(3.14*r*r)
  r=5.4cm
  n=60 degree
  A=15.26 sq. cm
  i guess please confirm from others
  
• 10 years agoHelpfull: Yes(3) No(0)
• angle made by minute hand in 10 minutes is 60 degree.
  hence area=3.14*(5.4)^2*(60/360)=15.3 cm^2
• 10 years agoHelpfull: Yes(2) No(0)
• 4.86 pi cm^2
  
  (angle/360)*(pi)*r*r
  angle covered in 10 minutes is 60
  pi*r*r/6
• 10 years agoHelpfull: Yes(1) No(0)
• area of dial=pi*r*r;
  i.e pi*(5.4)^2
  area covered in 60 min=pi*29.16
  in 1 min= pi*29.16/60
  in 10 min=(pi*29.16/60)*10;
• 10 years agoHelpfull: Yes(1) No(0)
• pi*(r^r)*(60/360)
  area=pi*(5.4)^(2*60)
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• area=pi*(5.4)^2*60/360
  =pi*(5.4)^2/6 cm^2
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• why it is angle/360????????
  
• 10 years agoHelpfull: Yes(0) No(1)