There are 20 balls which are red, blue or green. If 7 balls are green and the sum of red balls and green balls is less than 13, at most how many red balls are there?
Option
A. 4
B. 5
C. 6
D. 7

• r+g+b=20
  g=7
  
  r + g < 13
  => r + 7 < 13
  => r < 6
  => at most 5 red balls
  
  B. 5
• 10 years agoHelpfull: Yes(71) No(0)
• B. 5
  Green+Red is less than 13
  7+Maximum 5= 12 is less than 13
  So at most 5 red balls are there
• 10 years agoHelpfull: Yes(5) No(0)
• green=7
  red+green < 13
  7+g < 13 => g < 13-7 =>g < 6
  at most 5 red balls will be there
  
• 10 years agoHelpfull: Yes(1) No(0)
• GIVEN:
  RED + GREEN + BLUE = 20
  GREEN = 7
  
  SOLUTION:
  R + G < 13
  THEREFORE R + 7 < 13
  SO r < 6
  ANS: AT most 5 red balls
  
  B. 5
• 10 years agoHelpfull: Yes(1) No(0)
• r+g+b=20
  g=7
  
  r + g < 13
  => r + 7 < 13
  => r < 6
  => at most 5 red balls
  
  ans=5
• 10 years agoHelpfull: Yes(1) No(0)
• red + green < 13
  red + 7 < 13
  red
• 10 years agoHelpfull: Yes(0) No(2)
• Given R + B + G = 17; G = 7; and R + G < 13. Substituting G = 7 in the last equation, We get R < 6. So maximum value of R = 6
  
• 10 years agoHelpfull: Yes(0) No(6)
• ans:B
  I think somethng wrng with data.. balls in bag are red,blue AND green...then
  R+G+B=20 & G=7;
  R+G R=5
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• 5 is correct. 13-7=5
• 10 years agoHelpfull: Yes(0) No(2)
• red + green + blue=20
  green=7
  red + green < 13
  at most red + green=12
  blue can be at most (20-12)=8
  red=20-(8+7)
  = 5
  option b
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• r+g
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• B
  GB=7
  GB+RB
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• either 6 or 7
• 10 years agoHelpfull: Yes(0) No(2)
• My Answer is: B
  
  Green Red Blue
  7 + ? + ? = 20 Balls
  
  Green + Red < 13
  7 + 6 = 13 (condition didn't exist)
  
  7 + 5 = 12 (condition satisfies here)
  
  So at most 5 red balls will be there.
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• if g=7
  and r+g
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• r+g+b=20
  g=7
  r+7
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• (B): g=7
  g+r
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• r+b+g = 20
  r+g=13 as g=7
  r+g
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• 7==gball
  rball+gballrball+7
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• Red Green Blue
  ans -> 5 7 8
  4 7 9
  3 7 10
  2 7 11
  1 7 12
  0 7 13
  
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• given g->>7 balls then think ..for a sec and read ques..r+g
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• as r+g
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• option:b
  n(s)=20
  n(G)=7
  n(R+G)-13(i.e less than )
  n(R)+n(G)-13=0
  n(R)+7-13=0
  n(R)=6 but at most is 5 red ball
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• 13-7=6 isans
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