3i-Infotech
Company
Numerical Ability
Probability
The probability of two events A and B are0.25 and 0.40 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________
Read Solution (Total 12)
-
- we are apply that formula..............
P(AorB)=P(A)+P(B)-P(A AND B)
=.25+.40-.15
=.50
but the probability of neither A nor B=1-.50
=.50
so correct ans is .50 - 10 years agoHelpfull: Yes(9) No(2)
- 0.5
Probability neither A nor B occur=
1-[(Prob. A occur +Prob. B occur)-Prob. both A & B occurs)]
=1-[(0.25+0.40)-0.15]
=0.5 - 10 years agoHelpfull: Yes(6) No(0)
- P(AUB)'=1-P(AUB)=1-(P(A)+P(B)-P(AnB))=1-P(A)-P(B)+P(AnB)=1-0.25-0.40+0.15=0.50
- 10 years agoHelpfull: Yes(1) No(0)
- 1-p(a+b)
=1-0.25-0.40+0.15
=0.50 - 10 years agoHelpfull: Yes(1) No(0)
- .45 by solvingwe get the ans
- 10 years agoHelpfull: Yes(1) No(0)
- neither A nor B= 1- (A or B) = 1- ( .25 + .40 - .15) =.50
- 10 years agoHelpfull: Yes(0) No(0)
- p(aUb)=p(a)+p(b)-p(a intersection b)
p(aUb)=0.50
ans=p(aUb)-0.50
ans=0.50 - 10 years agoHelpfull: Yes(0) No(0)
- Given data:-
p(A)=0.25
p(B)=0.40
p(A & B)=0.15
p(A nor B)=0.25+0.40-0.15=0.50 - 10 years agoHelpfull: Yes(0) No(0)
- the ans is
,50 - 10 years agoHelpfull: Yes(0) No(0)
- (1-0.25)*(1-0.40)=0.75*0.60
- 9 years agoHelpfull: Yes(0) No(1)
- P( notA & notB ) = .75 x .60 = .45
- 8 years agoHelpfull: Yes(0) No(0)
- occurrence of both is p(a and b)=p(a)+p(b)-p(a or b)
not to occur is p(a nor b)+occur p(a and b)=1 - 7 years agoHelpfull: Yes(0) No(0)
3i-Infotech Other Question