Two taps a and fill a tank respectively in 6 and 8 min. if these two taps are opened one by one for one min each then how long will it take for the tank to fill up?

• 6 min 45 sec
  
  In 1 min
  1st tap fills =1/6
  2nd tap fills =1/8
  
  In 2 min they together fill = 1/6 +1/8 = 14/48=7/24
  In 6 min they fill = 7/24*3 =21/24
  
  Remaining fraction to be filled = 3/24 = 1/8
  
  For 1st pipe
  1/6 filled ---- 1min
  1/8 filled -----x min
  x = 6/8 min = 45 sec
  
  Time taken to fill tank = 6 min 45 sec
  
• 10 years agoHelpfull: Yes(1) No(0)
• For 1 min 1/6th willbe filled.
  For 2mins 1/6 + 1/8 = 7/24 will be filled.
  for 4 mins 14/24
  for 6mins 21/24 will be filled...
  In 7th min 1/6 will be filled but need is only 1 - 21/24 =1/8
  so let x be the time ...
  x(1/6)=1/8
  X=3/4 mins =3/4 * 60 =45 secs..
  so, a total of 6mins 45 secs is required to fill the tank...
• 10 years agoHelpfull: Yes(1) No(0)
• 48/7 min
  
  In 1 min
  1st tap fills =1/6
  2nd tap fills =1/8
  
  In 2 min they together fill = 1/6 +1/8 = 14/48=7/24
  
  Time taken to fill tank = 24/7*2 = 48/7 minutes
• 10 years agoHelpfull: Yes(0) No(1)
• There are two solutions for this question.
  
  Since it is not given which tap is opened first
  i)if tap A is opened first then it takes 6 min 45 sec
  
  6 min 45 sec
  
  In 1 min
  1st tap fills =1/6
  2nd tap fills =1/8
  
  In 2 min they together fill = 1/6 +1/8 = 14/48=7/24
  In 6 min they fill = 7/24*3 =21/24
  
  Remaining fraction to be filled = 3/24 = 1/8
  
  For 1st pipe
  1/6 filled ---- 1min
  1/8 filled -----x min
  x = 6/8 min = 45 sec
  
  Time taken to fill tank = 6 min 45 sec
  
  ii) if tap B is opened first then it takes 7mins
  
  In 1 min
  1st tap fills =1/6
  2nd tap fills =1/8
  
  In 2 min they together fill = 1/6 +1/8 = 14/48=7/24
  In 6 min they fill = 7/24*3 =21/24
  
  Remaining fraction to be filled = 3/24 = 1/8
  
  For 2nd pipe
  1/8 is filled in 1 min
  
  Time taken to fill tank = 7mins
• 10 years agoHelpfull: Yes(0) No(0)