A person walking at 5/6th of his usual speed is 40 mins late to his office.What is his usual travel time to his office?

• 4 hours
  
  Let the usual travel time be t ,speed s and distance d
  distance/speed = time
  d/s = t ---(1)
  
  d/(5/6*s) = t+40 ---(2)
  6/5 * d/s = t + 40
  6/5 * t = t+40
  1/6 * t = 40
  t = 40*6 = 240 min
  =4 hours
• 10 years agoHelpfull: Yes(2) No(3)
• 3 hours 20 min
  
  Let the usual travel time be t ,speed s and distance d
  distance/speed = time
  d/s = t ---(1)
  
  d/(5/6*s) = t+40 ---(2)
  6/5 * d/s = t + 40
  6/5 * t = t+40
  1/5* t = 40
  t = 40*2 = 200 min
  =3 hours 20 min
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• sorry..the correct ans is 3hrs 20 min
• 10 years agoHelpfull: Yes(1) No(0)
• it is given that 5/6 of normal speed makes him 40 min late..
  so we can coculde that..the new tym is 6/5 as distance is same..there for
  6/5 means incresae of tym is 1/5....(1+1/5) =6/5WHICH IS 40 MIN
  HENCE 1/5 OF NORMAL IS=40
  NORMAL TYM IS 200 MIN
  ITS CURRENT TYM TAKEN TO REACH OFFICE IS 240 MIN...4 HRS
• 10 years agoHelpfull: Yes(0) No(0)
• 
  Let the usual travel time be t ,speed s and distance d
  distance/speed = time
  d/s = t ---(1)
  
  d/(5/6*s) = t+40 ---(2)
  6/5 * d/s = t + 40
  6/5 * t = t+40
  1/5 * t = 40
  t = 40*5 = 200 min
  =3 hr 40 minute
  ans-3 hr 40 min
  
  
• 10 years agoHelpfull: Yes(0) No(1)