FIND THE VALUE OF X ?
(2/7)^-8*(7/2)^-2=(2/7)^X

• (2/7)^-8*(7/2)^-2=(2/7)^x
  Now, (7/2)^8*(2/7)^2=(2/7)^x
  on solving,
  (7/2)^6=(2/7)^x
  (2/7)^-6=(2/7)^x
  Thus, x=-6.
• 10 years agoHelpfull: Yes(16) No(0)
• (2/7)^-8*(7/2)^-2=(2/7)^x
  (2/7)^-8*(2/7)^2=(2/7)^x
  Now as the bases are same we can solve the powers
  -8+2=x
  -6=x or x=-6.
• 10 years agoHelpfull: Yes(7) No(0)
• x=-6
  bases are equal so powers are add
• 10 years agoHelpfull: Yes(5) No(1)
• (2/7)^-8*1/(7/2)^2=(2/7)^x
  (2/7)^-8*(2/7)^2=(2/7)^x
  ==>x=-6
• 10 years agoHelpfull: Yes(3) No(0)
• x=-6
  when bases are equal and multiply thm then their powers are add
• 10 years agoHelpfull: Yes(2) No(0)
• bases are equal so ....
  -8+(-2)=x
  -10=x
  x=-10
• 10 years agoHelpfull: Yes(1) No(7)