find the value of-
16C4

• nCr = n!/r!*(n-r)!
  16C4 = 16!/4!*12!
  ==>16*15*14*13*12!/4*3*2*1*(12!)
  ==>1820
  
  Ans : 1820
• 10 years agoHelpfull: Yes(29) No(1)
• 16c4 ans is 1820.
  
  the formula for this is nCr= n!/r!(n-r)! that means 16!/4!(16-4)!
  (16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1)/(4*3*2*1)*(12*11*10*9*8*7*6*5*4*3*2*1)
  = 16*15*14*13/(4*3*2*1)
  =by multiplying u wil get 1820
  
• 10 years agoHelpfull: Yes(2) No(0)
• nCr=(n!)/(r!*(n-r)!)
  In this case,n=16 and r=4 so 16C4=16!/(4!*(16-4)!)=16!/(4!*12!)=(16*15*14*13)/(4*3*2*1)=3640
  Ans: 3640
• 10 years agoHelpfull: Yes(1) No(3)
• Ans:1820,16!/(15!4!)
• 10 years agoHelpfull: Yes(0) No(2)
• 16C4= 16!/(12!*4!)
  = 1820
• 10 years agoHelpfull: Yes(0) No(0)
• 16*15*14*13*(12!)/(16!-4!)*4*3*2*1
  
  =16*15*14*13/4*3*2* = 1820. ans
• 9 years agoHelpfull: Yes(0) No(0)
• 16c4=13*14*15*16/24
  =10*13*14
  =1820
• 7 years agoHelpfull: Yes(0) No(0)