LCM of 3 nos is 120 which of the following no must not be their HCF
a. 8 , b.24 c.12 d.24 and 30

• b and d is same.and also these all are divisible by 120 which is the LCM of 3 nos.HCF is divisible by LCM.so there is no option mentioned which will not be their HCF
• 12 years agoHelpfull: Yes(12) No(6)
• 120=2*2*2*3*5
  now
  8=2*2*2
  24=2*2*2*3
  12=2*2*3
  30=2*3*5
  here every nos are belongs within it's LCM so no one is possible
  but in d there are two options if we see it from that corner (means if 24 is HCF then 30 must not be the HCF) then ans will be d
• 12 years agoHelpfull: Yes(12) No(12)
• None of the options are right.
• 12 years agoHelpfull: Yes(8) No(6)
• the options are wrong
  
• 9 years agoHelpfull: Yes(1) No(1)