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Numerical Ability
Permutation and Combination
how many number of three digit numbers can be formed usingzs numbers 2,3,4,5 in which no repeatation..?
Read Solution (Total 9)
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- 4*3*2=24
1 place of digit can be filled with 4 no
2 place of digit can be filled with 3 no (as 1 is already filled and not available)
3 place of digit can be filled with 2 no
so 24 ways - 10 years agoHelpfull: Yes(14) No(0)
- P(4,3);
4p3(permutations)
4*3*2=24 numbers - 10 years agoHelpfull: Yes(9) No(0)
- Ans : 24
no. of possible way to fill 1st place is 4
since repitation is not allowed ,no. of possible way to fill 2nd place is 3
no. of possible way to fill 3rd place is 2
no. of three digit numbers formed is 4x3x2=24 - 10 years agoHelpfull: Yes(6) No(0)
- 4!=24 as nos are to be made from 4 nos
- 10 years agoHelpfull: Yes(5) No(0)
- ans:24
4*3*2=24 - 10 years agoHelpfull: Yes(3) No(0)
- - - -
the number of way to fill first place is 4
the number of way to fill second place is 3
the number of way to fill third place is 2
hence total number of ways would be 4*3*2 == 24ways - 10 years agoHelpfull: Yes(2) No(0)
- the spaces can be filled in following manner..
2 3 4
_ _ _
soo 4*3*2=24 - 10 years agoHelpfull: Yes(1) No(0)
- when repeatation does not occurs then we do permutation
so P(4,3)=24
ans:24 - 10 years agoHelpfull: Yes(1) No(0)
- no. of ways=4*3*2=24
- 8 years agoHelpfull: Yes(0) No(0)
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