A Product is supported each week by the same three customer service Representatives (CSR's). Last month the first CSR took 450 calls, the second took 350 calls, and the third took 300 calls. This month the job will consists of 1500 calls. If the three CSR's each increase their work proportionately, how many more calls will the first CSR take this month than last month? Explain in steps

• Last month ratio C1 : C2 : C3 = 45 : 35 : 30 => 9 : 7 : 6
  
  This month total calls = 1500
  9x + 7x + 6x = 1500
  x= 1500/22 = 750/11
  
  C1 ratio = 9 * 750/11 = 613.6 => 614 approximately
  C2 ratio = 7 * 750/11 = 477.2
  C3 ratio = 6 * 750/11 = 409
  Calls first CSR ll take more than last month = 614 - 450 = 164
  
  Ans : 164
• 10 years agoHelpfull: Yes(56) No(0)
• Calls taken by first csr1 = 450, csr2 = 350, csr3=300
  so their ratio is = 450:350:300
  ==> 9:7:6
  
  Total calls for the next month ==>1500
  
  9x+7x+6x = 1500
  22x=1500
  x=1500/22 ==> 750/11
  
  first CSR1 ratio == 9*(750/11) ==> 613.6 ==>614
  
  First month csr1 calls = 450
  
  So increase in calls for the coming month = 614 - 450 ==> 164
• 10 years agoHelpfull: Yes(2) No(0)
• product supported by each is same
  so,
  3 mp=1500
  each mp is 500
  calls take increase by first csr is
  500-450=50
  Ans is ->50
• 10 years agoHelpfull: Yes(0) No(8)