if a+b:b+c:c+a=6:7:8 and a+b+c=14, then value of c is?

• taking common ratio as k
  we get
  a+b=6k
  b+c=7k
  c+a=8k
  adding these 3 we get
  2(a+b+c)=21k
  or a+b+c=(21k/2)
  now given a+b+c=14
  comparing these 2 we get 21k/2=14 or k=(14*2/21)=4/3
  putting the value of k we get a+b=6*4/3=8
  so c=(a+b+c)-(a+b)=14-8=6
• 13 years agoHelpfull: Yes(19) No(0)
• (A+B):(B+C):(C+A) = 6:7:8
  LET THE COMMON MULTIPLE BE "X"
  A+B = 6X
  B+C = 7X
  A+C = 8X
  2(A+B+C) = 21X
  2*14=21X
  X = (4/3)
  A+B = 6*4/3 = 8
  8+C = 14
  C = 6
• 13 years agoHelpfull: Yes(4) No(0)