an isosceles triangle with sides 13 13 10 and there is a circle inscribed it .find the radius of circle?

• ans: 3.33
  
  height of triangle = √(13^2 - (10/2)^2) = 12
  
  area of triangle = r * s
  where, r = radius of inscribed circle & s=(a+b+c)/2
  
  area of triangle = 1/2 *b*h = 1/2 *10 *12 = 60
  
  s = (13+13+10)/2 = 18
  r = area of triangle / s = 60/18 = 10/3 = 3.33
• 10 years agoHelpfull: Yes(5) No(1)
• 3.33
  
  Radius of incircle of a triangle,
  r = 2*Area of triangle/perimeter of triangle
  
  Area of triangle = 1/2*base*height
  base = 10
  height = sqrt(13^2 - 10^2)
  = 12
  
  Area = 1/2*10*12
  =60
  
  Perimeter = 13+13+10
  =36
  
  Radius, r = 2*60/36
  =10/3
  =3.33
  
• 10 years agoHelpfull: Yes(3) No(2)