A Company finds that 62 of applicants pass its hiring test if 10212 applicants took the test last year and

10212+(10212*23)/100=12560 applicants took the test this year.
(12560*62)/100=7787applicant pass the hiring test.
failed student=12560-7787=4773
10 years agoHelpfull: Yes(9) No(1)
as 62% passed so failed 38%
and no of appeared dis year is 10212+23%10212=10212+2348.76=12560.76
failed=38%12560.76=4773
10 years agoHelpfull: Yes(6) No(0)
i think
10212 applicants filed in last year and this year candidates were 23% more of previous number of candidates
so candidates appearing this year are 10212+(10212*.23)=12561 (approx)
now 62% passes the hiring test so
passed candidates= .62*12561=7788 (approx)
thus candidates who failed this year=12561-7788=4473
ans could be 4473
10 years agoHelpfull: Yes(3) No(1)
10212+ 23%of 10212 = 12560, 62% of 12560 = 7787,
10212-7787 = 4773
10 years agoHelpfull: Yes(3) No(3)
is this method correct?
10212+23%= 10212.23
38% fail
38%*10212.23=3881
ans: 3881
10 years agoHelpfull: Yes(1) No(15)
no. of candidates took test this year=10212+23% of 10212=(1021200+234876)/100=12560.76=12560
no. of candidates fail this year=68%-100%=38%
38/100*12560=4773
10 years agoHelpfull: Yes(1) No(0)
10212+(10212*23)/100=12560 applicants took the test this year.
(12560*62)/100=7787applicant pass the hiring test.
failed student=12560-7787=4773
10 years agoHelpfull: Yes(1) No(0)
39733 calculate using maths
10 years agoHelpfull: Yes(0) No(8)

.....................................................A Company finds that 62% of applicants pass its hiring test. if 10212 applicants took the test last year and 23% more applicants took the test this year, how many

applicants failed this year?