There are 3 boys and 4 girls. We have to arrange any 1 boy at the centre and any 2 girls at corners. In how many methods these persons can be arranged.
OPTIONS:
1) 432
2) 488
3) 512
4) 580
5) 624
6) 725
7) 864
8) 1024
9) 1200
10) none of these

• solved on daily puzzle.
  4 persons can be placed in 4 unconditional places in 4*3*2= 24 ways
  4 girls can be placed in 6 ways at two corner and by replacing corners among two girls, there are 12 ways.
  3 boys can be placed in centre in 3 ways.
  
  so total methods = 24*12*3 = 864
• 13 years agoHelpfull: Yes(14) No(1)
• 1 boy in center 3C1 = 3
  2 girls at corner 4C2=12
  but now 4 (2 girl + 2 boys) is remaining to arrange around to centre so 4! = 24
  "and" is using here so we will multiply it . if in this question "or" would there insted of "and" then we will use addition..
  3*12*24= 864
• 13 years agoHelpfull: Yes(8) No(4)
• arrangement of two girls at corner is=4p2=4*3=12
  arrangement of one boy at centre is =3p1=3
  arrangement of remaining two girls and two boys =4p4=4*3*2=24
  TOTAL ARRANGEMENT IS=12*3*24=864
• 13 years agoHelpfull: Yes(6) No(1)
• 4c2 * 2! = 12 - 2girls at corner
  3c1 = 3 - 1boy at center
  4! = 24 - remaining 4
  hence, 12 * 3 * 24 = 864
  
• 13 years agoHelpfull: Yes(5) No(2)
• methods for arranging 1 boy at centre = 3
  methods of arranging 2 girls at corner = 4*3 = 12
  methods of arranging remaining 4 persons = 4*3*2*1 = 24
  so total methods = 3*12*24 = 864
• 13 years agoHelpfull: Yes(2) No(3)
• One boy can be picked up and arranged in 3c1 ways.
  two girls for the extremes can be picked up and arranged in 4c2 * 2! ways
  others can be arranged in 4! ways.
  
  therefore totral number of ways = 3C1 * 4C2 * 2! * 4! = 864
  Therefore option 7) 864 is the answer
• 13 years agoHelpfull: Yes(0) No(1)
• 3 boys and 4 girls,1 boy @ center & 2 girls @ corner
  lets take yke 1 for boy and 2 for girls
  then sequence will be 2 1 2 1 2 1 2
  take sum of 1st three and last three digit
  answer will be 515.
  answer out of this ten option is
  10) none of these
  
• 13 years agoHelpfull: Yes(0) No(1)
• total 7 position
  middle one for boy only=3 ways
  ends fo girls= 4c2 *2!
  remainig 4 position n 4 people = 4!
  total = 3*4c2*2!*4!=864
• 13 years agoHelpfull: Yes(0) No(0)
• 432
  it will be 4c2 * 3c1 * 4! =432
• 13 years agoHelpfull: Yes(0) No(0)
• 7
  
  the boy to be seated at the centre can be chosen in 3c1 ways.
  two girls to be seated at the corners can be selected in 4p2 ways,, as we have to arrange them also, thereby using permutation.
  now we have 2 vacant seats each on either side of the central boy,, so the remaining two girls and 2 boys can arrage themselves in 4! ways among these seats.
  so total no of ways= 4p2 * 3c1 * 4! = 864
  
  c -> combinations
  p -> permutations
• 13 years agoHelpfull: Yes(0) No(0)