A walk 20m towards north east.B walk towards east 8m and then 12m south.Now calculate Distance between A and B?(asked in today's cts online test)

• its coming 30.4m
  since 1st triangle we get 18.31
  and extra 12 so 18.31+12=30.31=30m
• 10 years agoHelpfull: Yes(18) No(5)
• Ans:30.32
  first triangle:
  20^2=AB^2+8^2
  AB^2=400-64=336
  AB=root of 336=4*4.58=18.32
  Thus 18.32+12= 30.32
• 10 years agoHelpfull: Yes(7) No(1)
• 26.68
  square root of((20cos45-8)^2+(20sin45+12)^2)=26.85
  by using distance between two coordinates
• 10 years agoHelpfull: Yes(4) No(0)
• Its coming 24.08m i.e 24m.
  After solving 1st triangle v get one side valve as x^2=336
  2nd trangle vl give the distance that s 580under root=24
• 10 years agoHelpfull: Yes(3) No(0)
• sqrt(20^2-8^2)=sqrt(336)=18.33
  
  so 12+18.33=30.31=30m
• 10 years agoHelpfull: Yes(3) No(0)
• Solution cant be understood.please explain it clearly..
  
• 10 years agoHelpfull: Yes(2) No(0)
• N /A
  W-|-E /
  S 20m /
  /
  /
  C/---------|D
  8 m |
  |12m
  |
  |
  |
  |B
  so the AD^2=AC^2+CD^2
  =400+64
  AD^2= 464
  AD= 21.54
  AD+DB=21.54+12= 33.54(ans)
  
• 10 years agoHelpfull: Yes(2) No(0)
• /___ he walk 20m north east
  than we can apply pathagash....
  16+8 =AB = 24
  
• 10 years agoHelpfull: Yes(1) No(0)
• 1)20m north east
  2)8m east then 12 south
  solve 2)triangle by pythagoras get 14.42(sqrt(8^2+12^2))
  14.422+20=34.422m
• 10 years agoHelpfull: Yes(1) No(0)
• distance between A and B is 20.4 m
• 10 years agoHelpfull: Yes(0) No(1)
• using a pythageons therems
  
• 9 years agoHelpfull: Yes(0) No(0)
• mine is coming 31.32
  it would have been better if options were given
• 8 years agoHelpfull: Yes(0) No(0)