Six years hence,a fathers age will be three times his son's age and three years ago the fathers age is nine times as old as his son. the fathers present age is
Option
a) 24 years
b) 28 years
c) 30 years
d) 40 years

• Let "f" nd "s" be the father's nd son's present age respectively
  (f+6) = 3(s+6)
  f=3s+18-6
  f=3s+12
  
  f-3 = 9(s-3)
  f = 9s-27+3
  f=9s-24
  
  Equate "f"
  9s-24 = 3s+12
  6s = 36
  s=6
  f=3(6)+12
  f=30
  
  Ans : 30 years
• 10 years agoHelpfull: Yes(48) No(0)
• 3 yr hence
  father son
  x-3 9(x-3)
  9x-27=x-3
  x=3-> this is son's age 3 year ago
  therefore present age of son is 6yr
  ----------------------------
  and fathers age=9x=9*3=27+3=30
  27 is before 3 yrs so add 3into it.,result=30yr
  
• 10 years agoHelpfull: Yes(3) No(0)
• Let son's age be x years
  
  Father's age is 3 times of his son age = 3*x= 3x
  
  6 year's hence
  
  x + 6 = 3x + 6
  
  3 Year's ago the Fathers age is 9 tines the age of his son
  
  9( x + 6 + 3 ) = 3x + 6
  
  9(x + 9) = 3x + 6
  
  9x + 81 = 3x + 6
  
  6x = 72
  
  x = 72/6
  
  x = 12
  
  6 six Years Hence the fathers present age is age = 3 (12) + 6
  
  = 24+6
  
  = 30 years
  
• 8 years agoHelpfull: Yes(0) No(0)
• let so son age and father age there years was X and 9X respectively.
  6 year hence: ( X +6)+3 =9X+9
  therefore 3(X+9)=9X+9
  X=3
  father present age=9X+3=30
• 7 years agoHelpfull: Yes(0) No(0)