Elitmus
Exam
Logical Reasoning
Seating Arrangement
log x base a+log x base b +log x base c>1?
a) log x base a>1
b)a>b>c>0
Read Solution (Total 3)
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- both statement is required
log x base a + log x base b + log x base c > 1
for log to be defined a,b,c,x > 0
a) log x base a > 1 => x > a
b) a > b > c > 0
from a & b
x > a > b > c > 0
since, log x base a > 1
so, log x base a + log x base b + log x base c > 1 as 2nd & 3rd has a positive value. - 10 years agoHelpfull: Yes(28) No(3)
- log x base a>1 = a> x is given so there is no chance for negative value of
log x base b + log x base c so alone a ex plane this.
- 10 years agoHelpfull: Yes(2) No(6)
- a,b,c >1 then both are required for satisfaction
but if 0 - 10 years agoHelpfull: Yes(0) No(1)
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