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Exam
Numerical Ability
Permutation and Combination
A basket contains 3 bananas and 4 apples. In how many ways can select one or more fruits?
Read Solution (Total 3)
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- In 3 bananas, we can select: 0 or 1 0r 2 or 3 bananas =4 ways
In 4 Apples ,we can select: 0 or 1 or 2 or 3 or 4 apples =5 ways
=> Bananas or apples are selected=5*4 ways=20
=> But condition is ,we can select one or more fruits,so(zero banana and zero apple combination is omitted)
=> so,finally number of ways of selecting one or more fruits is=20-1=19
- 10 years agoHelpfull: Yes(3) No(0)
- 19 ways
Number of ways in which atleast one object may be selected out of 'p' alike objects of one type and 'q' alike objects of second type is,
(p+1)*(q+1)-1 = (3+1)*(4+1) - 1
=4*5-1
=20-1
=19
- 10 years agoHelpfull: Yes(1) No(0)
- 3 bananas + 4 apples = 7 fruits
no. of ways to select one or more fruits = 7C1 + 7C2 + ...+ 7C7 = (2^7 -1) - 10 years agoHelpfull: Yes(0) No(2)
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