A man walked a certain distance south and then the same distance plus 7km due west.He is now 13km from his starting point.What are the distances south and west that he walked?".

• 5 Km & 12 Km
  
  If a man walked distance(in km) 'x' towards south & then 'x+7'towards west.
  Distance from starting point=Hypotenuse of a right triangle with sides x & (x+7)
  So 13^2=x^2+(x+7)^2
  x^2+7x-60=0 or (x+12)(x-5)=0, so x=5
  Distance towards west=x+7=5+7=12 km.
• 10 years agoHelpfull: Yes(30) No(1)
• 5 km and 12 km
  suppose he walked x km in south and x+7 km in west
  then x^2 +(x+7)^2=169
  =>2x^2+14x-120=0
  =>x^2 +7x-60=0
  =>(x+12)(x-5)=0
  then x=-12,or 5
  but distance can't be negative so x=5
  
• 10 years agoHelpfull: Yes(2) No(0)
• Ans: 5km to south and 12 km towards west.
  Let the distance covered as he goes south be x km
  Since he covers the same distance and an additional distance of 7 km in west, therefore distance covered is (x+7)km
  According to Pythagoras Theorem,
  x^2+(x+7)^2= 13^2
  Solving for x, we get x=5km (south)
  so 5+7=12km (west)
• 10 years agoHelpfull: Yes(1) No(0)
• 5 12
  x^2+(x+7)^2=13^2
  x=5
  12
• 10 years agoHelpfull: Yes(0) No(0)
• 5km to south and 12 km to west
  12^2+5^2=13^2
• 10 years agoHelpfull: Yes(0) No(0)
• ans-5 km towards south and 12km toward west.
  let the man walked x km south.therefore he walked x+7 west.
  so we can write x^2+(x+7)^2=169
  from here we can find x=5
• 9 years agoHelpfull: Yes(0) No(0)
• distance travelled towards south is 5 km and towards west is 12 km.By phythagoras theorem.
• 9 years agoHelpfull: Yes(0) No(0)
• south-5km,west=12km
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• let he walked x km south.
  and then x+7 km towards west.
  Now the total distance from starting point is 13.
  This forms a right angled triangle.
  so
  x^2+(x+7)^2=169
  => x^2+x^2+14x+49=169
  => 2x^2+14x-120=0 -----------eqn 1
  dividing eqn 1 by 2
  we get
  x^2+7x-60=0
  => (x+12)(x-5)=0
  => x=-12 or x=5
  Since distance cant be negative so x=5
  Hence he walked 5 km south and then (5+7)=12 km west.
• 9 years agoHelpfull: Yes(0) No(0)
• (x^2)+(x+7)^2=(13^2)
  by solving we get x = 5
  so, south distance is 5 and west distance is 5+7=12
• 9 years agoHelpfull: Yes(0) No(0)
• apply Pythagoras
  2x^2+49+14x=169
  solve
  ans x=5 x+7=12
• 9 years agoHelpfull: Yes(0) No(0)