M4maths
Maths Puzzle
Logical Reasoning
Letter Series
. If in coded language
MAMTA = 8
SAUMYA = 80
MONIKA = 35
then
RASHMI = ?
Options 1) 16
2) 26
3) 42
4) 38
5) 14
6) 81
7) 39
8) 14
9) 27
10)None of these
Read Solution (Total 6)
-
- A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
MAMTA = (13)(1)(13)(20)(1) = 28-20 = 8 (Sum of Odd no - Sum of Even no)
SAUMYA = (19)(1)(21)(13)(25)(1) = 80-0 = 80
MONIKA = (13)(15)(14)(9)(11)(1) = 49-14 = 35
Similarly
RASHMI = (18)(1)(19)(8)(13)(9) = 42-26 = 16
- 10 years agoHelpfull: Yes(6) No(1)
- MAMTA ka code hai-13 1 13 20 1
mean odd no. ek sath or even ek sath
13+1+13+1=28
bacha 20
28-20=8
SAUMYA- 19 1 21 13 25 1
all are even so
add karne pe =80
waise hi
RASHMI-18 1 19 8 13 9
odd ek sath 1+19+13+9=42
even ek sath 18+8=26
42-26=16 - 10 years agoHelpfull: Yes(2) No(0)
- A=1, B=2,....,Z=26
subtract sum of even no. from sum of odd no., we get
MAMTA=(13+1+13+1)-20=8
similarly
RASHMI=(1+19+13+9)-(18+8)=16 - 10 years agoHelpfull: Yes(1) No(1)
- a=1,b=2,c=3............ z=26;
MAMTA=(13+1+13+1)-20=8
SO
RASHMI=(1+19+13+9)-(18+8)=16
ANSWER= 16 - 10 years agoHelpfull: Yes(0) No(3)
- in above question sum of odd place value of character in alphabet subtract to sum of even place of character in alphabet.
so that
RASHMI
R=18
A=1
S=19
H=8
M=13
I=9
ANSWER IS=(1+19+13+9)-(18+8=16
- 10 years agoHelpfull: Yes(0) No(0)
- convert in digits
ALL odds digits - oll even digits=16
- 10 years agoHelpfull: Yes(0) No(0)
M4maths Other Question