the length of canvas 1.1 m wide required to build a conical tent of height 14 m and the floor area 346.5 sq metre

• 525 m
  
  Floor area = 346.5
  pi*r^2 = 346.5
  r^2 = 346.5/pi
  r^2 = 110.25
  r = 10.5 m (r ---> radius of base)
  
  Surface area of conical tent = pi*r*l
  l----> slant height
  l = sqrt(h^2+r^2)
  =sqrt(14^2+10.5^2)
  =17.5m
  
  Surface area = pi*10.5*17.5
  = 577.5 m^2
  
  Area of canvas = surface area of conical tent
  length of canvas*width of canvas = 577.5
  length of canvas*1.1 = 577.5
  length of canvas = 525 m
  
• 10 years agoHelpfull: Yes(4) No(0)
• pi*r^2 = 346.5
  r^2 =346.5*7/22=441/4
  r =21/2
  then length L=sqrt(r^2 + h^2)=sqrt(441/4+(14)^2)=sqrt(1225/4)=35/2
  So, area of canvas needed =
  pi*r*L=(22/7)*(21/2)*(35/2) m^2
  =(33*35)/2 m^2
  Length of canvas =(33*35)/(2*1.1)m = 525 m.
• 10 years agoHelpfull: Yes(2) No(0)