If 9 is 6th term of an A P If sum of 2nd 3rd and 5th term is equal to

let AP be a,(a+d),(a+2d),...

6th term = 9 => a+5d=9 ----(1)

2nd + 3rd + 5th = 4th
=> a+d + a+2d + a+4d = a+3d
=> 2a + 4d = 0
=> a + 2d = 0 ---(2)

(1)-(2) => d = 3 , a= -6

8th term = a+7d = -6 + 7*3 = 15
10 years agoHelpfull: Yes(3) No(0)
A6=a+5d=9......(1)
A2+A3+A5=A4
a+d+a+2d+a+4d=a+3d
3a+7d=a+3d
a=-2d.......(2)
Putting (2) in (1) we get
-2d+5d=9
d=3
a=-6
8th term=-6+7*3=21-6=15
10 years agoHelpfull: Yes(0) No(0)
a6=9 so a+5d=9 and a2+a3+a5=a4 hence by this equation we can infer a+2d=0 hence we conclude dat a= -6 , d=3 hence a8= 15
10 years agoHelpfull: Yes(0) No(0)
15
Because the series is -6,-3,0,3,6,9,12,15
10 years agoHelpfull: Yes(0) No(0)

If 9 is 6th term of an A.P. If sum of 2nd,3rd and 5th term is equal to its 4th term. Find 8th term of A.P.