-x^2+4x-5-cos^2(5x)=0
this equation has ......... no of roots.

• -x^2 + 4x - 5 - cos^2(5x) = 0
  => -x^2 + 4x - 5 = cos^2(5x)
  
  -x^2 + 4x - 5 < 0 for any x & cos^2(5x) > 0 for any x
  
  so, given eqn has no real soln.
  no. of real roots = 0
  
• 10 years agoHelpfull: Yes(3) No(0)
• -x^2+4x-5-cos^2(5x)=0
  ===>x^2-4x+5=-cos2(5x)
  since x has power two so it has two root values
• 10 years agoHelpfull: Yes(0) No(2)