How many 4 digit integers formed between >990 and <5000 by using 0,4,5,7,8,9 repetition of integers are allowed

• ans: 216
  
  numbers are of 4-digits > 990 and < 5000
  
  thousand place can be filled by 4 only in one way
  as repetition is allowed , rest three places can be filled in 6 ways each
  
  total no. formed = 1*6*6*6 = 216
• 10 years agoHelpfull: Yes(36) No(6)
• - - - -
  
  let these be 4 digits.
  first digit can be filled in single way i.e. 4
  rest 3 digits can be any of 6
  because repetition is allowed
  hence 6*6*6 = 216 ways
  
• 10 years agoHelpfull: Yes(13) No(2)
• Answer : 221
  
  this is because it starts from 990. it can be considered as 0990 (a four digit number). So 0994,0995,0997,0998,0999 (5). [6*6*6 + 5 = 221].
• 10 years agoHelpfull: Yes(6) No(4)
• if we consider 0991,0992,0993...0999
  Answer: 432
  _,_,_,_
  1) thousand place can be taken only by 0 or 4 ie 2 ways
  2)hundredth can be take in 6 ways
  3)tens position can be taken by 6 ways
  4)ones position can be taken by 6 ways
  2*6*6*6=432
• 10 years agoHelpfull: Yes(2) No(11)
• numbers are of 4-digits > 990 and < 5000
  thousand place can be filled by 4 only in one way
  as repetition is allowed
  total no. formed = 1*6*6*6 = 216
  4 in one way so and the rest in six ways so only 216
• 10 years agoHelpfull: Yes(2) No(2)
• greater than 990 is 994 995 997 998 999. and let the 4 digit number be ---- . in this first digit occupies only 4 according to the ques. the rest 3 places can be filled by 6C3 times . so 6*5*4= 120. so the final answer is 120+ 5= 125
• 10 years agoHelpfull: Yes(1) No(5)
• of the total 6 digits given, 1st place can be filled only by 4.
  4---. So, the rest 3 places can be occupied by remaining 5 numbers in 5^3-5 ways i.e 125-5= 120 ways
• 10 years agoHelpfull: Yes(1) No(4)
• in first 0 cannot come.so only chance of 5 digits. bt remaining all the places all the six digits can be placed so that it is 6. 5*6*6*6=1080...
• 10 years agoHelpfull: Yes(1) No(1)
• 256
  
  1*6*6*6
• 10 years agoHelpfull: Yes(0) No(3)
• 4001 ecause 1000 is he four digit number and 1000 to 2000 1000 digits and 2000 to 3000 1000 3000 to 4000 and 4000 to 5000 and 1000 1 totally 4001
• 10 years agoHelpfull: Yes(0) No(3)
• at the thousand place 0&4 can be but it can be count only above 990 thats why 0 can come only 0991, 0992........0999 after that 4 can come at that place 1. And remaining can come at that place 6 ways so
  Ans will be .... (1*6*6*6)+9=225.
• 9 years agoHelpfull: Yes(0) No(1)