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Maths Puzzle
Numerical Ability
If sum of first 2 terms of a GP is thrice first term. & 4th term of GP is 256. Find 9th term of GP
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- let GP be a,ar,ar^2,... where a = first term, r = common ratio
T1 + T2 = 3*T1 => a+ar=3a => 1+r=3 => r=2
T4 = 256 => a*r^3 = 256 => a*2^3=256 => a = 32
T9 = a*r^8 = 32*2^8 = 2^13 = 8192 - 10 years agoHelpfull: Yes(0) No(0)
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