total no of 4 digit natural numbers divisible by either 101 or 7.

• 1363
  
  Four digit terms divisible by 7 are
  1001,1008,...9996
  This is an AP whose nth term = 1st term+(n-1)*difference
  9996 = 1001+(n-1)*7
  n=1286
  
  Four digit terms divisible by 101 are
  1010,1111,1212,1313....9898,9999
  9999 = 1010+(n-1)*101
  n = 90
  
  Common terms for both the series are,
  1414,2121,2828,3535,....9898
  9898 = 1414 + (n-1)*707
  n = 13
  
  Total no. of 4 digit natural numbers divisible by 101 or 7 = 1286 + 90 - 13
  =1363
• 10 years agoHelpfull: Yes(0) No(3)