A train covered a distance at a uniform speed if the train had been 6 km hr faster it would

From formula
D=st
given
D=(s+6)(t-4)=st-4s+6t-24.......>1
D=(s-6)(t+6)=st+6s-6t-36)......>2

from 1&2
-4s+6t=24
6s-6t=36 .....>3

on solving
2s=60 ==> s=30 km/h
(3)==> 6(30)-6t=36
t= 24 h
.
. . D=30(24) = 720 km

Ans: D= 720 km
10 years agoHelpfull: Yes(8) No(6)
Let the distance is x km, speed is y km/hr, time is z hr
Then x=y/z -------------1
From given data we get
y+6=x/t-4------------------2;
y-6=x/t-6 ------------------3
by solving 2&3 we get y=30km/hr
from 1&2 we get t=24 hr
then x =t*y= 720 km
10 years agoHelpfull: Yes(3) No(0)
from the above question,we can form 2 equations,
d/(s+6)-d/s=4....................(1)
d/s-d/(s+6)=4....................(2)

on solving,we get s=30km/hr.
now putting this value in first equation u will get distance as 720km.
10 years agoHelpfull: Yes(3) No(0)
assume dist=x;
assume uniform speed=p;
(x/p)-(x/p+6)=4..............(1)
(x/p-6)-(x/p)=6...............(2)
then sole and get 720 Ans
10 years agoHelpfull: Yes(1) No(0)
by short tricks
distance= [t1*s(s+x1)] /x1
speed = [x1x2(t1+t2)] / [x1t2-x2t1]
first find out the value of speed then distance.
Ans:720
10 years agoHelpfull: Yes(0) No(0)
the distance is same.
so velocity and time are inversly proportional to each other.
therefore, s+6=1/t-4.
s-6=1/t+6.
t=1/s-6 -6
substitite in equation 1
and solve it .
then Ans is 720.
6 years agoHelpfull: Yes(0) No(0)

A train covered a distance at a uniform speed .if the train had been 6 km/hr faster it would have been 4 hour less than schedule time and if the train were slower by 6 km/hr it would have been 6 hrs more.find the distance.