Miscellaneous Company Exam
Company
Numerical Ability
Algebra
How much is √(20+√(20+√(22+√(8+√(1)))))?
a)20
b)9
c)71
d)5
Read Solution (Total 3)
-
- 5
by calculate all roots - 10 years agoHelpfull: Yes(1) No(1)
- ==>5
sq.root of 1 is 1
then 8+1==9
sq.root of 9 is 3
then 3+22==25
sq.root of 25 is 5
then 20+5==25
sq.root of 25 is 5
then 20+5==25
sq.root of 25 is 5
ans:5 - 10 years agoHelpfull: Yes(1) No(0)
- d)5
Rootover 1 =1
Then 8+1=9
Again rootover 9=3
3+22=25
Rootover 25= 5
Then we are getting the result as 5 - 10 years agoHelpfull: Yes(0) No(0)
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